1. Δ_mixS = 0 at constant T and P 2. Δ_mixV ≠ 0 at constant T and P 3. Δ_mixH = 0 at constant T and P 4. Δ_mixG = 0 at constant T and P

Answer: 3. Δ_mixH = 0 at constant T and P For an ideal solution the A-B interactions equal the A-A and B-B interactions. Therefore Δ_mixH = 0 and Δ_mixV = 0 . Mixing is spontaneous and entropy increases, so Δ_mixS > 0 and Δ_mixG < 0 . Only option (3) is correct.

Topic: Ideal and non-ideal solutions· Solutions

For an ideal solution, the correct option is :

1. \(\Delta_{mix}S = 0\) at constant T and P

2. \(\Delta_{mix}V \neq 0\) at constant T and P

3. \(\Delta_{mix}H = 0\) at constant T and P

4. \(\Delta_{mix}G = 0\) at constant T and P

Doubtly Asked 30 Oct 2026 NEET UG 2019 Practice test neet Save WhatsApp Report

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Answer: 3. \(\Delta_{mix}H = 0\) at constant T and P

For an ideal solution the A-B interactions equal the A-A and B-B interactions. Therefore \(\Delta_{mix}H = 0\) and \(\Delta_{mix}V = 0\). Mixing is spontaneous and entropy increases, so \(\Delta_{mix}S > 0\) and \(\Delta_{mix}G < 0\). Only option (3) is correct.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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For an ideal solution, the correct option is :

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