Elimination reaction of 2-Bromo-pentane to form pent-2-ene is :(a) β-Elimination reaction(b) Follows Zaitsev rule(c) Dehydrohalogenation reaction(d) Dehydration reaction

1. (a), (b), (c)

2. (a), (c), (d)

3. (b), (c), (d)

4. (a), (b), (d)

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Answer: 1. (a), (b), (c)

2-Bromopentane \(\mathrm{CH_3CHBrCH_2CH_2CH_3}\) loses HBr with alcoholic KOH.

(a) H is removed from the carbon beta to the carbon bearing Br: \(\beta\)-elimination. True.
(b) The more substituted alkene, pent-2-ene, is the major product: Zaitsev rule. True.
(c) Loss of H and halogen is dehydrohalogenation. True.
(d) Dehydration is loss of water from alcohols. False.

Answer: (a), (b), (c), option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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