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Answer: 2. Only NaCl

Passing HCl gas raises the \(\mathrm{Cl^-}\) concentration. When the ionic product \([\mathrm{Na^+}][\mathrm{Cl^-}]\) exceeds the solubility product of NaCl (common-ion effect), NaCl crystallises. \(\mathrm{CaCl_2}\) and \(\mathrm{MgCl_2}\) are much more soluble and stay in solution.

Answer: only NaCl, option (2).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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