1. c : 1 2. 1 : 1 3. 1 : c 4. 1 : c²

Answer: 2. 1 : 1 In an electromagnetic wave the energy is shared equally between the electric and magnetic fields. Electric energy density =1/2ε₀E² and magnetic energy density =B²/2μ₀ . Using E=cB and c²=1/μ₀ε₀ : 1/2ε₀c²B²=B²/2μ₀ So the contributions are in the ratio 1 : 1.

Topic: EM waves, characteristics and transverse nature· Electromagnetic Waves

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is : (c = speed of electromagnetic waves)

1. c : 1

2. 1 : 1

3. 1 : c

4. 1 : $c^2$

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Answer: 2. 1 : 1

In an electromagnetic wave the energy is shared equally between the electric and magnetic fields.

Electric energy density $=\tfrac12\epsilon_0E^2$ and magnetic energy density $=\tfrac{B^2}{2\mu_0}$. Using $E=cB$ and $c^2=\tfrac{1}{\mu_0\epsilon_0}$:

$$\frac12\epsilon_0c^2B^2=\frac{B^2}{2\mu_0}$$

So the contributions are in the ratio 1 : 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is : (c = speed of electromagnetic waves)

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