1. 0.5 kg/m ³ 2. 0.2 kg/m ³ 3. 0.1 kg/m ³ 4. 0.02 kg/m ³

Answer: 2. 0.2 kg/m ³ Use the ideal gas equation in density form: P=ρ RT/M . M=2×10⁻³ kg/mol, T=300 K, P=2.49×10⁵ Pa. ρ=PM/RT=frac2.49×10⁵×2×10⁻³8.3×300=0.2\ kg/m³ Answer: option 2.

Topic: Equation of state of a perfect gas, work done on compressing a gas· Kinetic Theory of Gases

A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27^°C.Its density is : (R = 8.3 J mol^-1 K^-1)

1. 0.5 kg/m$^3$

2. 0.2 kg/m$^3$

3. 0.1 kg/m$^3$

4. 0.02 kg/m$^3$

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Answer: 2. 0.2 kg/m$^3$

Use the ideal gas equation in density form: $P=\dfrac{\rho RT}{M}$.

$M=2\times10^{-3}$ kg/mol, $T=300$ K, $P=2.49\times10^5$ Pa.

$$\rho=\frac{PM}{RT}=\frac{2.49\times10^5\times2\times10^{-3}}{8.3\times300}=0.2\ \text{kg/m}^3$$

Answer: option 2.

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A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27^°C.Its density is : (R = 8.3 J mol^-1 K^-1)

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