A 40 μF capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is, nearly :

1. 1.7 A

2. 2.05 A

3. 2.5 A

4. 25.1 A

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Answer: 3. 2.5 A

Capacitive reactance $X_C=\dfrac{1}{2\pi fC}$.

$$X_C=\frac{1}{2\pi\times50\times40\times10^{-6}}\approx79.6\ \Omega$$$$I_{rms}=\frac{V_{rms}}{X_C}=\frac{200}{79.6}\approx2.5\ \text{A}$$

Answer: option 3.

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