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Topic: Reactance, impedance, LCR series circuit, resonance· Electromagnetic Induction and Alternating Currents

A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π/3. If instead C is removed from the circuit, the phase difference is again π/3 between current and vo…

A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is \(\frac{\pi}{3}\). If instead C is removed from the circuit, the phase difference is again \(\frac{\pi}{3}\) between current and voltage. The power factor of the circuit is :

1. zero

2. 0.5

3. 1.0

4. \(-1.0\)

1 answer

Best answer

Answer: 3. 1.0

With L removed, the circuit is RC: \(\tan\phi=\dfrac{X_C}{R}\). With C removed, it is RL: \(\tan\phi=\dfrac{X_L}{R}\).

Both phase angles are \(\pi/3\), so \(X_C=X_L\).

In the full series LCR circuit the reactances cancel, which is resonance: \(Z=R\), and

$$\cos\phi=\frac RZ=1$$

Power factor is 1.0. Answer: option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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