1. 2.4π×10⁻⁴ T m A ⁻¹ 2. 8.0×10⁻⁵ T m A ⁻¹ 3. 2.4π×10⁻⁵ T m A ⁻¹ 4. 2.4π×10⁻⁷ T m A ⁻¹

Answer: 1. 2.4π×10⁻⁴ T m A ⁻¹ Relative permeability μ_r=1+chi=1+599=600 . μ=μ₀μ_r=4π×10⁻⁷×600=2.4π×10⁻⁴\ T m A⁻¹ The magnetising field 1200 A/m is not needed for permeability. Answer: option 1.

Topic: Para-, dia- and ferromagnetism, effect of temperature· Magnetic Effects of Current and Magnetism

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m^-1. The permeability of the material of the rod is :(μ_0 = 4π×10^-7 T m A^-1)

1. $2.4\pi\times10^{-4}$ T m A$^{-1}$

2. $8.0\times10^{-5}$ T m A$^{-1}$

3. $2.4\pi\times10^{-5}$ T m A$^{-1}$

4. $2.4\pi\times10^{-7}$ T m A$^{-1}$

Doubtly Asked 30 Oct 2026 NEET UG 2020 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 1. $2.4\pi\times10^{-4}$ T m A$^{-1}$

Relative permeability $\mu_r=1+\chi=1+599=600$.

$$\mu=\mu_0\mu_r=4\pi\times10^{-7}\times600=2.4\pi\times10^{-4}\ \text{T m A}^{-1}$$

The magnetising field 1200 A/m is not needed for permeability. Answer: option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m^-1. The permeability of the material of the rod is :(μ_0 = 4π×10^-7 T m A^-1)

1 answer

Your answer