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Topic: Viscosity, Stokes' law, terminal velocity, streamline and turbulent flow, critical velocity· Properties of Solids and Liquids

The velocity of a small ball of mass M and density d, when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is d/2, then the viscous force acting on the ball will be :

1. \(\frac{Mg}{2}\)

2. Mg

3. \(\frac{3}{2}Mg\)

4. 2Mg

1 answer

Best answer

Answer: 1. \(\frac{Mg}{2}\)

Key idea: at constant (terminal) velocity the net force is zero: weight = buoyancy + viscous force.

Volume of ball \(V=M/d\). Buoyant force \(=V\cdot\dfrac d2\cdot g=\dfrac{Mg}{2}\).

Viscous force \(=Mg-\dfrac{Mg}{2}=\dfrac{Mg}{2}\). Option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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