A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is :

1. 0.0628 s

2. 6.28 s

3. 3.14 s

4. 0.628 s

Doubtly Asked 30 Oct 2026 NEET UG 2021 Practice test neet Save WhatsApp Report

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Answer: 4. 0.628 s

Key idea: find k from the stretch, then use \(T=2\pi\sqrt{m/k}\).

\(k=\dfrac Fx=\dfrac{10}{0.05}=200\ \mathrm{N/m}\)

\(T=2\pi\sqrt{\dfrac{2}{200}}=2\pi\times0.1=0.628\ \mathrm s\). Option 4.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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