1. 1/2ε₀E² 2. ε₀EAd 3. 1/2ε₀E²Ad 4. E²Ad/ε₀

Answer: 3. 1/2ε₀E²Ad Key idea: energy density in an electric field is 1/2ε₀E² ; multiply by the volume between the plates. U=1/2ε₀E²× Ad . Option 3. Option 1 is only the energy per unit volume.

Topic: Energy stored in a capacitor· Electrostatics

A parallel plate capacitor has a uniform electric field 'E' in the space between the plates. If the distance between the plates is 'd' and the area of each plate is 'A', the energy stored in the capacitor is : (ε_0 = permittivity of free space)

1. \(\frac{1}{2}\varepsilon_0E^2\)

2. \(\varepsilon_0EAd\)

3. \(\frac{1}{2}\varepsilon_0E^2Ad\)

4. \(\frac{E^2Ad}{\varepsilon_0}\)

Doubtly Asked 30 Oct 2026 NEET UG 2021 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 3. \(\frac{1}{2}\varepsilon_0E^2Ad\)

Key idea: energy density in an electric field is \(\tfrac12\varepsilon_0E^2\); multiply by the volume between the plates.

\(U=\tfrac12\varepsilon_0E^2\times Ad\). Option 3. Option 1 is only the energy per unit volume.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

A parallel plate capacitor has a uniform electric field 'E' in the space between the plates. If the distance between the plates is 'd' and the area of each plate is 'A', the energy stored in the capacitor is : (ε_0 = permittivity of free space)

1 answer

Your answer