1. 2n-1/2n 2. 2n-1/2n+1 3. 2n+1/2n-1 4. 2n/2n-1

Answer: 2. 2n-1/2n+1 Key idea: distance in the n-th second from rest is S_n=1/2a(2n-1) . S_n∝(2n-1) and S_(n+1)∝(2n+1) , so dfracS_nS_(n+1)=2n-1/2n+1 . Option 2.

Topic: Uniformly accelerated motion relations· Kinematics

A small block slides down on a smooth inclined plane, starting from rest at time t = 0. Let S_n be the distance travelled by the block in the interval t = n − 1 to t = n. Then, the ratio S_nS_n+1 is :

1. \(\frac{2n-1}{2n}\)

2. \(\frac{2n-1}{2n+1}\)

3. \(\frac{2n+1}{2n-1}\)

4. \(\frac{2n}{2n-1}\)

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Answer: 2. \(\frac{2n-1}{2n+1}\)

Key idea: distance in the n-th second from rest is \(S_n=\tfrac12a(2n-1)\).

\(S_n\propto(2n-1)\) and \(S_{n+1}\propto(2n+1)\), so \(\dfrac{S_n}{S_{n+1}}=\dfrac{2n-1}{2n+1}\). Option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A small block slides down on a smooth inclined plane, starting from rest at time t = 0. Let S_n be the distance travelled by the block in the interval t = n − 1 to t = n. Then, the ratio S_nS_n+1 is :

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