The ratio of the distances travelled by a freely falling body in the 1^st, 2^nd, 3^rd and 4^th second :

1. 1 : 1 : 1 : 1

2. 1 : 2 : 3 : 4

3. 1 : 4 : 9 : 16

4. 1 : 3 : 5 : 7

Doubtly Asked 30 Oct 2026 NEET UG 2022 Practice test neet Save WhatsApp Report

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Best answer

Answer: 4. 1 : 3 : 5 : 7

For a body falling from rest, the distance in the \(n\)th second is \(s_n=\tfrac12g(2n-1)\).

So the distances in 1st, 2nd, 3rd and 4th seconds are in the ratio \(1:3:5:7\) (Galileo's odd-number rule).

Option (4) is correct.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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