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Topic: Valence, oxidation states and chemical reactivity· Classification of Elements and Periodicity in Properties

In which one of the following arrangements the given sequence is not strictly according to the properties indicated against it ?

1. \(HF < HCl < HBr < HI\) : Increasing acidic strength

2. \(H_2O < H_2S < H_2Se < H_2Te\) : Increasing \(pK_a\) values

3. \(NH_3 < PH_3 < AsH_3 < SbH_3\) : Increasing acidic character

4. \(CO_2 < SiO_2 < SnO_2 < PbO_2\) : Increasing oxidizing power

1 answer

Best answer

Answer: 2. \(H_2O < H_2S < H_2Se < H_2Te\) : Increasing \(pK_a\) values

Key idea: check each trend.

  • 1: acidic strength HF < HCl < HBr < HI is correct (weaker H-X bond).
  • 2: down the group, acidity of \(\mathrm{H_2O
  • 3: acidic character of group 15 hydrides increases down the group: correct.
  • 4: oxidising power rises as the +4 state becomes less stable down group 14 (inert pair effect): correct.

Option 2 is the arrangement not strictly followed.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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