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Topic: Matter waves, de Broglie relation· Dual Nature of Matter and Radiation

The graph which shows the variation of the de Broglie wavelength (λ) of a particle and its associated momentum (p) is :

The graph which shows the variation of the de Broglie wavelength (\(\lambda\)) of a particle and its associated momentum (p) is :

four lambda vs p graphs, options 1-4

1. (graph)

2. (graph)

3. (graph)

4. (graph)

1 answer

Best answer

Answer: 1. (graph)

de Broglie wavelength is \(\lambda=h/p\), so \(\lambda\) is inversely proportional to \(p\).

The graph of \(\lambda\) against \(p\) is therefore a rectangular hyperbola: it falls steeply at small \(p\) and flattens towards the axis at large \(p\), never touching it. That is graph (1).

Graphs (2) and (3) are straight lines, and (4) rises with \(p\), none of which fit \(\lambda\propto 1/p\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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