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Answer: 4. \(90°\)

Use Snell's law: \(\sin60^\circ=\sqrt3\sin r\Rightarrow\sin r=\tfrac12\Rightarrow r=30^\circ\).

The reflected ray makes \(60^\circ\) with the normal, the refracted ray \(30^\circ\), on opposite sides. The angle between them is \(180^\circ-60^\circ-30^\circ=90^\circ\).

(This is Brewster's condition, \(\tan i=\sqrt3\).) Option (4).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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