Match List - I with List - II.List - I (Hydrides): (a) MgH_2 (b) GeH_4 (c) B_2H_6 (d) HFList - II (Nature): (i) Electron precise (ii) Electron deficient (iii) Electron rich (iv) IonicChoose the correct answer from the options given below :

1. (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

2. (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)

3. (a) - (iii), (b) - (i), (c) - (ii), (d) - (iv)

4. (a) - (i), (b) - (ii), (c) - (iv), (d) - (iii)

Doubtly Asked 30 Oct 2026 NEET UG 2022 neet Save WhatsApp Report

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Answer: 2. (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)

Key idea: classify hydrides by electron count.

\(\mathrm{MgH_2}\): metal hydride of s-block, ionic (iv).
\(\mathrm{GeH_4}\): group 14, exactly enough electrons for bonds, electron precise (i).
\(\mathrm{B_2H_6}\): too few electrons for normal bonds, electron deficient (ii).
HF: group 17 has lone pairs left over, electron rich (iii).

So (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii): option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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