In the neutral or faintly alkaline medium, KMnO_4 oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from

1. \(+6\) to \(+5\)

2. \(+7\) to \(+4\)

3. \(+6\) to \(+4\)

4. \(+7\) to \(+3\)

Doubtly Asked 30 Oct 2026 NEET UG 2022 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 2. \(+7\) to \(+4\)

Key idea: in neutral or weakly alkaline medium permanganate is reduced to \(\mathrm{MnO_2}\).

\(\mathrm{2MnO_4^-+H_2O+I^-\to2MnO_2+2OH^-+IO_3^-}\). Mn changes from +7 in \(\mathrm{MnO_4^-}\) to +4 in \(\mathrm{MnO_2}\). Option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?