The magnitude and direction of the current in the following circuit is 1. 1.5 A from B to A through E 2. 0.2 A from B to A through E 3. 0.5 A from A to B through E 4. 5/9 A from A to B through E

Answer: 3. 0.5 A from A to B through E In the loop the two cells oppose each other (10 V and 5 V), so the net emf is 10-5=5 V. The 10 V cell is stronger and decides the direction. Total resistance: 2+1+7=10 Ω . I=5/10=0.5 A. Current flows with the stronger cell, from A to B through E. The answer is 0.5 A from A to B through E.

Topic: Kirchhoff's laws and applications· Current Electricity

The magnitude and direction of the current in the following circuit is

loop ABCD with 2 ohm, cells 10 V and 5 V (E between), 1 ohm, 7 ohm

1. 1.5 A from \(B\) to \(A\) through \(E\)

2. 0.2 A from \(B\) to \(A\) through \(E\)

3. 0.5 A from \(A\) to \(B\) through \(E\)

4. \(\frac{5}{9}\) A from \(A\) to \(B\) through \(E\)

Doubtly Asked 30 Oct 2026 NEET UG 2023 Practice test neet Save WhatsApp Report

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Answer: 3. 0.5 A from \(A\) to \(B\) through \(E\)

In the loop the two cells oppose each other (10 V and 5 V), so the net emf is \(10-5=5\) V. The 10 V cell is stronger and decides the direction.

Total resistance: \(2+1+7=10\,\Omega\).
\(I=\dfrac{5}{10}=0.5\) A.

Current flows with the stronger cell, from A to B through E. The answer is 0.5 A from A to B through E.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The magnitude and direction of the current in the following circuit is

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