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Topic: Kirchhoff's laws and applications· Current Electricity

A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :

A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :

bridge circuit: 1 ohm and 2 ohm top (A-C-B), 3 ohm and 4 ohm bottom, wire CD between middle junctions, 50 V battery across A,B

1. 1.5 A

2. 2.0 A

3. 2.5 A

4. 3.0 A

1 answer

Best answer

Answer: 2. 2.0 A

Key idea: C and D are joined by a wire, so they are at the same potential. The circuit becomes two parallel pairs in series.

Left pair: \(1\parallel3=\tfrac34\ \Omega\). Right pair: \(2\parallel4=\tfrac43\ \Omega\). Total \(=\tfrac34+\tfrac43=\tfrac{25}{12}\ \Omega\), so

$$I=\frac{50}{25/12}=24\ \mathrm A$$

Voltage across the left pair \(=24\times\tfrac34=18\) V, across the right pair \(=24\times\tfrac43=32\) V. Currents: \(1\ \Omega\): 18 A; \(3\ \Omega\): 6 A; \(2\ \Omega\): 16 A; \(4\ \Omega\): 8 A.

At junction C: 18 A arrives, 16 A leaves through \(2\ \Omega\), so the wire CD carries \(18-16=2\) A.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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