The equilibrium concentrations of the species in the reaction A + B ⇌ C + D are 2, 3, 10 and 6 mol L^-1, respectively at 300 K. Δ G^° for the reaction is (R = 2 cal / mol K)

1. \(-13.73\) cal

2. 1372.60 cal

3. \(-137.26\) cal

4. \(-1381.80\) cal

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Answer: 4. \(-1381.80\) cal

Key idea: \(\Delta G^\circ = -2.303\,RT\log K\).

\(K = \frac{[C][D]}{[A][B]} = \frac{10 \times 6}{2 \times 3} = 10\), so \(\log K = 1\).

\(\Delta G^\circ = -2.303 \times 2 \times 300 \times 1 = -1381.8\) cal. Option 4.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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