Skip to content
doubtly

1 answer

Best answer

Answer: 3. \(-\) 413.14 calories

Key idea: for reversible isothermal expansion, \(w=-2.303\,nRT\log\dfrac{P_1}{P_2}\) (work done by the gas is negative in this convention).

$$w=-2.303\times1\times2\times298\times\log\frac{20}{10}=-2.303\times596\times0.3010\approx-413.14\ \mathrm{cal}$$

Option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.