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Answer: 2. propylamine

Key idea: follow each step.

  1. \(\mathrm{CH_3CH_2CH_2I+NaCN\to CH_3CH_2CH_2CN}\) (A, butanenitrile).
  2. Partial hydrolysis with \(\mathrm{OH^-}\) gives \(\mathrm{CH_3CH_2CH_2CONH_2}\) (B, butanamide).
  3. Hofmann bromamide reaction (\(\mathrm{Br_2/NaOH}\)) removes one carbon: \(\mathrm{CH_3CH_2CH_2NH_2}\).

C is propylamine, option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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