Topic: Vernier calipers and screw gauge· Experimental Skills

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero o…

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at $x = 0.1$ cm when the jaws of Vernier callipers are closed.

If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is

1. 5.18 cm

2. 5.08 cm

3. 4.98 cm

4. 5.00 cm

Doubtly Asked 30 Oct 2026 NEET UG 2025 Practice test neet Save WhatsApp Report

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Answer: 3. 4.98 cm

Key idea: reading $=$ MSR $+$ (VSR $\times$ least count) $-$ zero error.

10 VSD $=$ 9 MSD, so the least count $=1$ MSD $-1$ VSD $=0.1-0.09=0.01$ cm.

$$\text{Observed}=5+8\times0.01=5.08\ \mathrm{cm}$$

The zero of the vernier lies at 0.1 cm when the jaws are closed, so the zero error is $+0.1$ cm. Corrected diameter $=5.08-0.10=4.98$ cm.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero o…

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