A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale.The pitch of the screw gauge is :

1. 0.01 mm

2. 0.25 mm

3. 0.5 mm

4. 1.0 mm

Doubtly Asked 30 Oct 2026 NEET UG 2020 Practice test neet Save WhatsApp Report

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Answer: 3. 0.5 mm

Least count $=\dfrac{\text{pitch}}{\text{number of circular divisions}}$.

$$\text{pitch}=0.01\ \text{mm}\times50=0.5\ \text{mm}$$

Answer: option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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