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Answer: 1. 88 earth days

Key idea: Kepler's third law, \(T^2\propto r^3\).

$$\frac{T_{Mars}}{T_{Mercury}}=\left(\frac{r_{Mars}}{r_{Mercury}}\right)^{3/2}=4^{3/2}=8$$$$T_{Mercury}=\frac{687}{8}\approx86\ \text{days}$$

The orbit ratio is only "about 4", so the nearest option, 88 earth days, is the answer.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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