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Answer: 3. A and D only

Key idea: paramagnetic means unpaired electrons.

  • A: \(\mathrm{[NiCl_4]^{2-}}\), \(\mathrm{Ni^{2+}}\) d8, weak field Cl-, tetrahedral \(sp^3\): 2 unpaired, paramagnetic.
  • B: \(\mathrm{Ni(CO)_4}\), Ni(0) d10: diamagnetic.
  • C: \(\mathrm{[Ni(CN)_4]^{2-}}\), strong field, square planar \(dsp^2\): diamagnetic.
  • D: \(\mathrm{[Ni(H_2O)_6]^{2+}}\), d8 octahedral: 2 unpaired, paramagnetic.
  • E: \(\mathrm{Ni(PPh_3)_4}\), Ni(0) d10: diamagnetic.

A and D only: option (3).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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