1. SCN ^- < F ^- < C ₂ O ₄²⁻ < CN ^- 2. SCN ^- < F ^- < CN ^- < C ₂ O ₄²⁻ 3. F ^- < SCN ^- < C ₂ O ₄²⁻ < CN ^- 4. CN ^- < C ₂ O ₄²⁻ < SCN ^- < F ^-

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds ?

1. SCN\(^-\) < F\(^-\) < C\(_2\)O\(_4^{2-}\) < CN\(^-\)

2. SCN\(^-\) < F\(^-\) < CN\(^-\) < C\(_2\)O\(_4^{2-}\)

3. F\(^-\) < SCN\(^-\) < C\(_2\)O\(_4^{2-}\) < CN\(^-\)

4. CN\(^-\) < C\(_2\)O\(_4^{2-}\) < SCN\(^-\) < F\(^-\)

Doubtly Asked 30 Oct 2026 NEET UG 2020 Practice test neet Save WhatsApp Report

Best answer

Answer: 1. SCN\(^-\) < F\(^-\) < C\(_2\)O\(_4^{2-}\) < CN\(^-\)

From the spectrochemical series (weak to strong field): \(\mathrm{I^-

So the increasing order is \(\mathrm{SCN^-

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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