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Answer: 4. 6

Key idea: count the distinct kinds of hydrogen in 2-methylbutane, then count stereoisomers.

  • Two equivalent \(\mathrm{CH_3}\) on C-2: 1-chloro-2-methylbutane, has a chiral centre, 2 isomers.
  • C-2 H (tertiary): 2-chloro-2-methylbutane, 1.
  • C-3 \(\mathrm{CH_2}\): 2-chloro-3-methylbutane, chiral, 2.
  • C-4 \(\mathrm{CH_3}\): 1-chloro-3-methylbutane, 1.

Total = 2 + 1 + 2 + 1 = 6: option (4).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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