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If α=cos​​​​-1(3/5) , β=tan​​​​-1(1/3), where 0<α,β<π/4 , then α-β is equal to 

A) \(\sin^{-1} {9\over5\sqrt{10}}\) 

B)\(\tan^{-1} ({9\over14})\) 

C)\(\cos^{-1} {9\over5\sqrt{10}}\) 

D)\(\tan^{-1} ({9\over5\sqrt{10}})\)

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Correct answer is A) \(\sin^{-1} {9\over5\sqrt{10}}\) 

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