Electrostatics
- A parallel plate capacitor has capacitance \(C\) with air between the plates. A dielectric slab of dielectric constant 4 and thickness equal to half the plate separation is inserted between the plates. The new capacitance is Answer: B. 1.6 C C'=ε₀A/d-t+t/K=ε₀A/d/2+d/8=8/5·ε₀A/d=1.6C . 1
- The energy stored in a 10 μF capacitor charged to 100 V is Answer: A. 0.05 J U=1/2CV²=1/2×10⁻⁵×10⁴=0.05 J. 1
- Capacitors of 3 μF and 6 μF are connected in series across a 90 V supply. The potential difference across the 3 μF capacitor is Answer: A. 60 V C_s=2 μF, Q=180 μC, V₃=180/3=60 V. 1