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12th Science Maharashtra Board
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Mathematics & Statistics Part 2
Application of Definite Integration
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The area enclosed between the curves \(y=x^2\) and \(y=x\) is
Answer: B. 1/6 sq. unit ∫₀¹(x-x²)dx=1/2-1/3=1/6 .
Application of Definite Integration
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The area of the region bounded by the ellipse \(\frac{x^2}{16}+\frac{y^2}{9}=1\) is
Answer: C. 12π sq. units Area =π ab=π·4·3=12π .
Application of Definite Integration
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