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Purification and Characterisation of Organic Compounds
Empirical and molecular formula calculations
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An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is : [Atomic wt. of C is 12, H is 1]
Answer: 3. CH₃ Key idea: divide percentage by atomic mass, then take the simplest ratio. C: 78/12=6.5 ; H: 22/1=22 . Ratio H : C = 22/6.5≈3....
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