If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is \(\frac{x}{2}\) times its original time period. Then the value of \(x\) is:
Simple pendulum
Every question from past board papers on Simple pendulum, newest paper first. Open any question for its full worked answer.
NEET UG 2024 question paper (official, booklet S6)
Full paper →NEET UG 2022 question paper (official, booklet R6)
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Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is :
NEET UG 2018 question paper (official, booklet EE)
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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s\(^2\) at a distance of 5 m from the mean position. The time period of oscillation is