When the current in a coil falls uniformly from 2 A to zero in 0.05 s, an emf of 8 V is induced in it. The self-inductance of the coil is
A. 0.2 H
B. 0.1 H
C. 0.4 H
D. 0.8 H
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Answer: A. 0.2 H
\(L=\frac{e}{dI/dt}=\frac{8}{2/0.05}=0.2\) H.
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· 23 Oct 2026
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