Answer: x = 3, y = 2
\(D = \begin{vmatrix} 4 & 3 \\ 3 & -2 \end{vmatrix} = -8 - 9 = -17\)
\(D_x = \begin{vmatrix} 18 & 3 \\ 5 & -2 \end{vmatrix} = -36 - 15 = -51\)
\(D_y = \begin{vmatrix} 4 & 18 \\ 3 & 5 \end{vmatrix} = 20 - 54 = -34\)
\(x = \dfrac{D_x}{D} = \dfrac{-51}{-17} = 3\), \(y = \dfrac{D_y}{D} = \dfrac{-34}{-17} = 2\).