Answer: x = 3 or x = –1
a = 1, b = –2, c = –3.
\(b^2 - 4ac = 4 + 12 = 16\).
\(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \dfrac{2 \pm 4}{2}\)
\(x = \dfrac{6}{2} = 3\) or \(x = \dfrac{-2}{2} = -1\).
Best answer
Answer: x = 3 or x = –1
a = 1, b = –2, c = –3.
\(b^2 - 4ac = 4 + 12 = 16\).
\(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \dfrac{2 \pm 4}{2}\)
\(x = \dfrac{6}{2} = 3\) or \(x = \dfrac{-2}{2} = -1\).
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