Q.1 (B)(1) In the following figure Δ ABC, B – D – C and BD = 7, BC = 20, then find \(\dfrac{A(\Delta ABD)}{A(\Delta ABC)}\).[Figure: Δ ABC with point D on side BC; segment AD drawn.]

Doubtly Asked 24 Oct 2026 ssc 10th Save WhatsApp Report

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Answer: 7/20

Δ ABD and Δ ABC have the same height (the perpendicular from A to BC), so the ratio of their areas equals the ratio of their bases: \(\dfrac{A(\Delta ABD)}{A(\Delta ABC)} = \dfrac{BD}{BC} = \dfrac{7}{20}\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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Q.1 (B)(1) In the following figure Δ ABC, B – D – C and BD = 7, BC = 20, then find \(\dfrac{A(\Delta ABD)}{A(\Delta ABC)}\).[Figure: Δ ABC with point D on side BC; segment AD drawn.]

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