Q.1 (B)(ii) In the following figure, seg AE \(\perp\) seg BC, seg DF \(\perp\) line BC, AE = 4, DF = 6, then find \(\dfrac{A(\Delta ABC)}{A(\Delta DBC)}\).

Every question from past board papers on Similarity, newest paper first. Open any question for its full worked answer.
Q.1 (B)(ii) In the following figure, seg AE \(\perp\) seg BC, seg DF \(\perp\) line BC, AE = 4, DF = 6, then find \(\dfrac{A(\Delta ABC)}{A(\Delta DBC)}\).

Q.2 (B)(i) In the following figure, in \(\Delta PQR\), seg RS bisects \(\angle R\). If PR = 15, QR = 20, PS = 12, then find QS.

Q.3 (A)(i) In the following figure, in \(\Delta ABC\) ray BD bisects \(\angle ABC\), A – D – C, seg ED \(\parallel\) side BC, A – E – B, then to prove that \(\dfrac{AB}{BC} = \dfrac{AE}{EB}\), complete the following activity.

Activity : In \(\Delta ABC\), ray BD bisects \(\angle B\).
\(\therefore \dfrac{AB}{BC} = \dfrac{\text{____}}{\text{____}}\) .............. (I) (Angle bisector theorem)
In \(\Delta ABC\), seg ED \(\parallel\) side BC.
\(\therefore \dfrac{AE}{EB} = \dfrac{\text{____}}{DC}\) .............. (II) ____
\(\therefore \dfrac{AB}{\text{____}} = \dfrac{\text{____}}{EB}\) .............. from (I) and (II)
Q.4 (i) In the following figure, line \(l\) intersects side AB and side AC of \(\Delta ABC\) in points P and Q respectively. Show that \(\dfrac{A(\Delta APQ)}{A(\Delta ABC)} = \dfrac{AP \times AQ}{AB \times AC}\).

Q.1 (B)(1) The ratio of corresponding sides of similar triangles is 3 : 5, then find the ratio of their areas.
Q.2 (B)(1) Find QP using given information in the figure :

Q.3 (A)(1) In the following figure, seg XY || side AC. If 2AX = 3BX and XY = 9, complete the activity to find the value of AC.

Activity :
2AX = 3BX
∴ \(\dfrac{AX}{BX} = \dfrac{3}{2}\)
∴ \(\dfrac{AX + BX}{BX} = \dfrac{____ + ____}{2}\) .......... (By componendo)
\(\dfrac{AB}{BX} = \dfrac{____}{2}\)
Δ BCA ~ Δ BYX ............. (____ Test of similarity)
∴ \(\dfrac{BA}{BX} = \dfrac{AC}{XY}\) .............. (Corresponding sides of similar triangles)
∴ \(\dfrac{5}{____} = \dfrac{AC}{9}\)
∴ AC = ____
Q.4 (3) In Δ ABC, A-X-B and A-Y-C is such that segment XY || side BC. Segment XY divides Δ ABC in two equal areas, then find \(\dfrac{BX}{AB}\).
Q.1 (B)(1) In the following figure Δ ABC, B – D – C and BD = 7, BC = 20, then find \(\dfrac{A(\Delta ABD)}{A(\Delta ABC)}\).

Q.2 (B)(1) In Δ ABC, DE || BC. If DB = 5.4 cm, AD = 1.8 cm, EC = 7.2 cm, then find AE.

Q.3 (A)(1) In the following figure, XY || seg AC. If 2AX = 3BX and XY = 9. Complete the activity to find the value of AC.

Activity :
2AX = 3BX (Given)
∴ \(\dfrac{AX}{BX} = \dfrac{3}{\text{____}}\)
\(\dfrac{AX + BX}{BX} = \dfrac{3 + 2}{2}\) .......... (by componendo)
\(\dfrac{\text{____}}{BX} = \dfrac{5}{2}\) ................ (I)
Now Δ BCA ~ Δ BYX ............. (____ test of similarity)
∴ \(\dfrac{BA}{BX} = \dfrac{AC}{XY}\) .............. (corresponding sides of similar triangles)
∴ \(\dfrac{\text{____}}{\text{____}} = \dfrac{AC}{9}\) .............. from (I)
∴ AC = ____
Q.4 (1) In the following figure DE || BC, then :

(i) If DE = 4 cm, BC = 8 cm, A(Δ ADE) = 25 cm2, find A(Δ ABC).
(ii) If DE : BC = 3 : 5, then find A(Δ ADE) : A(□ DBCE).
Q.1 (A)(1) If \(\Delta ABC \sim \Delta DEF\), \(m\angle B = 60^\circ\), then \(m\angle E\) = ....................
Q.1 (B)(2) The ratio of corresponding sides of similar triangles is 3 : 5, then find the ratio of their areas.
Q.2 (A)(1) In the given figure, AR ⊥ BC, AR ⊥ PQ, then complete the activity for finding \(\dfrac{A(\Delta ABC)}{A(\Delta APQ)}\).

Activity :
\(\dfrac{A(\Delta ABC)}{A(\Delta APQ)} = \dfrac{____ \times AR}{PQ \times ____}\)
\(\therefore \dfrac{A(\Delta ABC)}{A(\Delta APQ)} = \dfrac{____}{____}\)
Q.2 (B)(1) In the following figure, in \(\Delta LMN\), ray MT bisects \(\angle LMN\).
If LM = 6, MN = 10, TN = 8, then find LT.

Q.4 (1) Δ ABC has sides of length 4 cm, 5 cm and 6 cm while Δ PQR has perimeter of 90 cm. If Δ ABC is similar to Δ PQR, then find the length of corresponding sides of Δ PQR.
Q.1 (A)(1) In \(\Delta ABC\) and \(\Delta PQR\), in a one to one correspondence of vertices, \(\dfrac{AB}{QR} = \dfrac{BC}{PR} = \dfrac{CA}{PQ}\), then ....................... statement is true.

Q.2 (B)(2) In \(\Delta PQR\), seg RS bisects \(\angle PRQ\). If PR = 15, RQ = 20, PS = 12, then find SQ.

Q.3 (A)(1) In the given figure, AB || CD || EF. If AC = 12, CE = 9, BD = 8, then complete the following activity to find DF.

Activity : AB || CD || EF
\(\therefore \dfrac{AC}{\text{____}} = \dfrac{\text{____}}{DF}\) ........... (Property of three parallel lines and their transversal)
\(\therefore \dfrac{12}{\text{____}} = \dfrac{\text{____}}{DF}\)
\(\therefore DF = \dfrac{8 \times 9}{\text{____}}\)
\(\therefore DF =\) ____
Q.3 (B)(4) If \(\Delta PQR \sim \Delta LMN\), \(9 \times A(\Delta PQR) = 16 \times A(\Delta LMN)\) and QR = 20, then find MN.
Q.1 (B)(1) If \(\Delta ABC \sim \Delta PQR\) and \(AB : PQ = 2 : 3\), then find the value of \(\dfrac{A(\Delta ABC)}{A(\Delta PQR)}\).
Q.3 (A)(1)

In Δ ABC, ray BD bisects ∠ABC, A – D – C, seg DE || side BC, A – E – B, then for showing \(\dfrac{AB}{BC} = \dfrac{AE}{EB}\), complete the following activity :
Proof :
In Δ ABC, ray BD bisects ∠B
∴ \(\dfrac{____}{BC} = \dfrac{AD}{DC}\) ............ (I) (____)
In Δ ABC, DE || BC
∴ \(\dfrac{____}{EB} = \dfrac{AD}{DC}\) ............ (II) (____)
\(\dfrac{AB}{____} = \dfrac{____}{EB}\) ............ [from (I) and (II)]
Q.3 (B)(4) Prove that, ‘If a line parallel to a side of a triangle intersects the remaining sides in two distinct points, then the line divides the side in the same proportion’.
Q.5 (1) □ ABCD is a trapezium, AB || CD, diagonals of trapezium intersects in point P.
Write the answers of the following questions :
(a) Draw the figure using given information.
(b) Write any one pair of alternate angles and opposite angles.
(c) Write the names of similar triangles with test of similarity.