The sum of the first \(n\) odd natural numbers is
A. \(n^2\)
B. \(n(n + 1)\)
C. \(\frac{n(n + 1)}{2}\)
D. \(2n - 1\)
A. \(n^2\)
B. \(n(n + 1)\)
C. \(\frac{n(n + 1)}{2}\)
D. \(2n - 1\)
Best answer
Answer: A. \(n^2\)
\(S_n = \frac{n}{2}[2(1) + (n - 1)2] = \frac{n}{2}(2n) = n^2\).
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