For an A.P., \(a = 6\) and \(d = 3\). Then \(S_6 = \)
A. \(63\)
B. \(81\)
C. \(75\)
D. \(99\)
A. \(63\)
B. \(81\)
C. \(75\)
D. \(99\)
Best answer
Answer: B. \(81\)
\(S_6 = \frac{6}{2}[2(6) + 5(3)] = 3(12 + 15) = 81\).
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