Two coins are tossed simultaneously. The probability of getting no head is
A. \(\frac{1}{2}\)
B. \(\frac{1}{4}\)
C. \(\frac{3}{4}\)
D. \(0\)
A. \(\frac{1}{2}\)
B. \(\frac{1}{4}\)
C. \(\frac{3}{4}\)
D. \(0\)
Best answer
Answer: B. \(\frac{1}{4}\)
\(S = \{HH, HT, TH, TT\}\). Only TT has no head: \(P = \frac{1}{4}\).
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