For a frequency distribution, \(\sum f_i x_i = 1860\) and \(\sum f_i = 60\). The mean is
A. 31
B. 30
C. 32
D. 1800
1 answer
Best answer
Answer: A. 31
\(\bar{X} = \frac{\sum f_i x_i}{\sum f_i} = \frac{1860}{60} = 31\).
Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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