A bulb is rated 100 W, 220 V. Its resistance is
A. 2.2 Ω
B. 484 Ω
C. 22000 Ω
D. 0.45 Ω
A. 2.2 Ω
B. 484 Ω
C. 22000 Ω
D. 0.45 Ω
Best answer
Answer: B. 484 Ω
\(R = \frac{V^2}{P} = \frac{220^2}{100} = \frac{48400}{100} = 484\) Ω.
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