100 g of water at 80 °C is mixed with 100 g of water at 20 °C. Assuming no heat loss, the final temperature is
A. 50 °C
B. 60 °C
C. 40 °C
D. 100 °C
A. 50 °C
B. 60 °C
C. 40 °C
D. 100 °C
Best answer
Answer: A. 50 °C
Heat lost = heat gained: \(100(80 - T) = 100(T - 20) \Rightarrow T = 50\) °C.
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