A ray of light is incident at 60° on the surface of a medium of refractive index \(\sqrt{3}\). The angle of refraction is
A. 30°
B. 45°
C. 60°
D. 90°
A. 30°
B. 45°
C. 60°
D. 90°
Best answer
Answer: A. 30°
\(\sin r = \frac{\sin 60°}{\sqrt{3}} = \frac{\sqrt{3}/2}{\sqrt{3}} = \frac{1}{2} \Rightarrow r = 30°\).
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