The critical velocity of a satellite revolving at height \(h\) above the earth (mass M, radius R) is

A. \(\sqrt{\frac{2GM}{R + h}}\)

B. \(\sqrt{\frac{GM}{R}}\,(R + h)\)

C. \(\frac{GM}{(R + h)^2}\)

D. \(\sqrt{\frac{GM}{R + h}}\)

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

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Answer: D. \(\sqrt{\frac{GM}{R + h}}\)

Gravitational force provides the centripetal force: \(\frac{mv^2}{R+h} = \frac{GMm}{(R+h)^2} \Rightarrow v_c = \sqrt{\frac{GM}{R+h}}\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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