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Answer: \(\dfrac{3}{13}\)

S : the 52 cards of the pack, so \(n(S) = 52\).

Event A : the card drawn is a face card. Each of the 4 suits has 3 face cards (king, queen, jack), so \(n(A) = 4 \times 3 = 12\).

\(P(A) = \dfrac{n(A)}{n(S)} = \dfrac{12}{52} = \dfrac{3}{13}\).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report
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