In triangle ABC, D and E are points on AB and AC such that DE ∥ BC. If AD = 4 cm and DB = 6 cm, what is the ratio of the area of triangle ADE to the area of trapezium DBCE?
A. 16 : 25
B. 2 : 3
C. 4 : 25
D. 4 : 21
A. 16 : 25
B. 2 : 3
C. 4 : 25
D. 4 : 21
Best answer
Answer: D. 4 : 21
Answer: (D) 4 : 21
Triangles ADE and ABC are similar with ratio AD : AB = 4 : 10 = 2 : 5, so their areas are in the ratio 4 : 25.
Area of DBCE = 25 − 4 = 21 parts. Required ratio = 4 : 21.
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