Two chords AB and CD of a circle intersect at a point P inside the circle. If AP = 6 cm, PB = 4 cm and CP = 3 cm, find PD.
A. 4.5 cm
B. 2 cm
C. 7 cm
D. 8 cm
A. 4.5 cm
B. 2 cm
C. 7 cm
D. 8 cm
Best answer
Answer: D. 8 cm
Answer: (D) 8 cm
Intersecting chords theorem: \(AP \times PB = CP \times PD\). \(6 \times 4 = 3 \times PD \Rightarrow PD = 8\) cm.
Log in or create a free account to answer this question.